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0=16+10x-4.9x^2
We move all terms to the left:
0-(16+10x-4.9x^2)=0
We add all the numbers together, and all the variables
-(16+10x-4.9x^2)=0
We get rid of parentheses
4.9x^2-10x-16=0
a = 4.9; b = -10; c = -16;
Δ = b2-4ac
Δ = -102-4·4.9·(-16)
Δ = 413.6
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-10)-\sqrt{413.6}}{2*4.9}=\frac{10-\sqrt{413.6}}{9.8} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-10)+\sqrt{413.6}}{2*4.9}=\frac{10+\sqrt{413.6}}{9.8} $
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